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Re: NFB101 Crisis!

by "Ian Iveson" <IanIveson.home@[EMAIL PROTECTED] > Apr 24, 2008 at 01:01 AM

Ian Thompson-Bell wrote

>>>>> I have just been working through the math for shunt 
>>>>> derived shunt applied NFB around an amp and Ican't get 
>>>>> the expected result.
>>>> Is that the same as voltage derived, current applied? I 
>>>> can never remember this stuff, sigh.
>>>>
>>> No, it's voltage derived, voltage applied. As a rule:
>>>
>>> Shunt = Voltage
>>> Series = Current
>>
>>
>> Thanks. Then how come your circuit employs "shunt 
>> derived" feedback?
>>
>
> Sorry, don't understand - the feedback network is fed from 
> the output voltage i.e. across or shunting the output. Is 
> that what you mean?
>
>> And perhaps you could answer the question you cut out 
>> from my post, considering I was good enough to answer 
>> yours:
>>
>
> My apologies, I must have missed it.
>
>> "Your maths is correct or we're both wrong.
>>
>> "I don't know if it helps to see it as Ao/(1+ß.(1+Ao))
>>
>
> Yes, I had it as that to start with but changed it to 
> 'show' the anomoly.
>
>> "You haven't explained why you believe there is an 
>> anomaly.
>> What led you to your erroneous expectation?"
>>
>
> I had expected *all* NFB forms (however derived or 
> applied) to reduce to Ao/(1+ß.Ao) but this one does not.


I find the four possible combinations of shunt/series 
feedback can be difficult to interpret, so it may be just 
me.

For shunt derived feedback I would expect to see a load and 
means of sensing the current through that load. An example 
would be the use of a small current-sensing resistor on the 
ground side of a loudspeaker to derive the feedback signal. 
Another example is the use of an unbypassed cathode 
resistor, which is shunt derived, series applied.

If the load is purely resistive, I can't see the difference 
between the two methods of derivation, because the current 
will always be in fixed pro****tion to the voltage.

Where the only load is the feedback path itself, which in 
your case is purely resistive, I can't see the difference 
either. The most obvious way to me of seeing your circuit, 
however, is that the feedback signal is derived from a 
voltage divider between output and input. It seems to me 
that is where the mysterious "1+" comes from...the fact that 
the feedback is not derived from a voltage divider between 
the output and ground...there's an extra Vin with respect to 
that.

Ian
 




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