by Ian Thompson-Bell <ruffrecords@[EMAIL PROTECTED]
>
Apr 22, 2008 at 04:04 PM
Iain Churches wrote:
> "Eeyore" <rabbitsfriendsandrelations@[EMAIL PROTECTED]
> wrote in message
> news:480DE286.CB70EB3C@[EMAIL PROTECTED]
>>
>> Iain Churches wrote:
>>
>>> The standard 6V3 winding would give 8.8V DC.
>> Not with rectifier voltage drops it won't. More like 6.8V.
>
> I did not include the rectifier losses.
>
> The AC is at about 235V here this afternoon. I have a
> Welter mains transformer on the bench in front
> of me. The heater winding is 6.3V at 3A reg 5%. With
> a BR156 rectifier and 10 000µF and drawing 3A I measure
> 7.6V across the electrolytic. What does a SS regulator
> require?
>
> Iain
>
>
Depends what you measure it with - a regular ac meter will not show the
ripple.
Given c.dV = i.dt then dV(pp ripple) = i.dt/C and using your values I get
dV = 3Ax10mS/10,000uF = 3V pp ripple!! assuming 50Hz mains and full wave
rectification.
Cheers
Ian
